You are given n wires each of resistance rΩ. What is the ratio of maximum to minimum resistance that can be obtained from these wires?
Answers
Answer:
maximum= nr
minimum= r/n
Explanation:
we can get maximum resistance when we add all resistance in series
Rs = nr
we can get minimum resistance when we add all resistance in parallel
Rp = r/n
Given : n wires each of resistance r ohm
To Find : ratio of maximum to minimum resistance possible with these wires
Solution:
n wires each of resistance r ohm
maximum resistance when in series
=r + r +r + ... + .. + n times
= rn
minimum resistance when all in parallel
= 1/(1/r + 1/r + 1/r + ... + ... n times)
= r/n
Ratio =rn/(r/n)
= n²
ratio of maximum to minimum resistance possible with these wires is n²
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