Question

You are given the following substances with their melting and boiling points. Substance Melting Point (0C) Boiling Point (0C) X -219 -183 Y 119 445 Z -15 78 Identify the physical states of X, Y and Z at room temperature (300C).

Answer 1

As Room temperature is 30°C.

For substance X mpt= -219 , bpt= -183

so, X will be in gaseous state at it will melt at -219°C and will boil to gas at -183°C.

For substance Y mpt= 119 , bpt= 445

So, Y will melt to liquid at 119 and will be gas after boiling at 445. hence it will be solid before melting at 119°C which is far above the room temperature.

For substance Z mpt= -15, bpt= 78

So, the substance Z will melt to liquid at -15 and will remain in liquid form till 78 °C. Hence it will be liquid at room temperature.

Answer 2

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As Room temperature is 30°C.

For substance X mpt= -219 , bpt= -183

so, X will be in gaseous state at it will melt at -219°C and will boil to gas at -183°C.

For substance Y mpt= 119 , bpt= 445

So, Y will melt to liquid at 119 and will be gas after boiling at 445. hence it will be solid before melting at 119°C which is far above the room temperature.

For substance Z mpt= -15, bpt= 78

So, the substance Z will melt to liquid at -15 and will remain in liquid form till 78 °C. Hence it will be liquid at room temperature.

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