you are given three resistance of 1ohm, 2ohm,3ohm how with the help pf these resistance you can get 6ohm,6/11ohm,1.5ohm
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1) to get 6 ohm
We connect the three resistors in series. so resistances are added to get the effective resistance: 1 + 2 + 3 = 6 Ω
2) to get 6/11 Ω
We connect all the resistances in parallel. The effective resistance be R.
1/R = 1/1 + 1/2 + 1/3 = 11/6
R = 6/11 Ω
3) to get 1.5 Ω
We connect 1 Ω and 2 Ω in series. Hence, resistance of the two will be 3 Ω. Then connect the 3 Ω resistance in parallel with the series connection of 1 Ω and 2 Ω.
so effective resistance = R
1/R = 1/(1+2) + 1/3 = 2/3
R = 3/2 Ω = 1.5 Ω
We connect the three resistors in series. so resistances are added to get the effective resistance: 1 + 2 + 3 = 6 Ω
2) to get 6/11 Ω
We connect all the resistances in parallel. The effective resistance be R.
1/R = 1/1 + 1/2 + 1/3 = 11/6
R = 6/11 Ω
3) to get 1.5 Ω
We connect 1 Ω and 2 Ω in series. Hence, resistance of the two will be 3 Ω. Then connect the 3 Ω resistance in parallel with the series connection of 1 Ω and 2 Ω.
so effective resistance = R
1/R = 1/(1+2) + 1/3 = 2/3
R = 3/2 Ω = 1.5 Ω
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Answer:
Firstly connected in series all resistance then we get 6 ohms... then we connect all resistance in parallel then we get 6/11...then last resistance 1and 2 ohms connect in series then we get 3ohms and 3ohms and 3 ohms connect in parallel then we get 1.5ohms
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