You are given two 1.5kohm resistors and six 15kohm resistors. Arrange these resistors as to provide an effective resistance value of 3.25kohm.
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Explanation:
arrange the 1.5kΩ in parallel connection and you will get a resistence of 0.75kΩ
now arrange the 15kΩ resistors also in parallel connectionand here you will get a resistence of 2.5kΩ
now you have 0.75kΩ resistence and 2.5kΩ resistence
connect both of the resistences in series connection and you are answered
0.75kΩ + 2.5kΩ = 3.25kΩ
in above "Ω" is symbol of ohm
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