You are interested in a short–term course in computer graphics after your examination. Write a letter to the Director, Fortune Graphics Computers, inquiring about their short–term courses and asking for all the necessary details. You are Ranjan/Ranjana of 28 A, Lajpat Nagar, New Delhi. *
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0.2 moles of solute (urea) =0.2 X molar mass of urea = 0.2 X 60=12 grams
0.8 moles of solvent (water) = 0.8 X molar mass of water = 0.8 X 18= 14.4 grams.
Mass of solution = Mass of solute + Mass of solvent
=12 + 14.4
26.4 grams
Volume =mass/density
=26.4/d mL =26.4/1000 dL
Molarity =0.1/26.4/1000 d
1/10 X 1000d/26.4
Molarity =100d/26.4
If density=0.21gm/mL putting this value in the above equation we get.
Molarity=100X0.21/26.4=0.79 M
if d=0.21 gm/mL Its volume=26.4/1000 X0.21
volume=0.12 L =0.12 X1000= 120 ml
Percentage of solution= mass/volume of solution
=26.4/120
=0.22%
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