You are Karishma of 119, Mall Road, Shimla. You are interested in doing a short term course in computer programming during your summer vacation. Write a letter to the Director Computer World, Sector 22, Chandigarh, inquiring about the duration of such a course and the terms and conditions for admission.
Answers
Required Letter:-
119, Mall road
Shimla
22.11.2020
To
The Director
Computer World
22, Chandigarh 01
Sub : Enquiry for admission
Sir,
With due respect, in the response to your advertisement in 'The Telegraph' dated 17th November, 2020, I wish to get myself enrolled in your institution to pursue the Basic Computer programming. I want to get the course during my summer vacation next year for a short term course. Inform me if you have such course there.
Let me know the following as soon as possible :
- Eligibility
- course fees
- Duration of course
- The probable routine
I hope ti receive an early reply from you.
Thanking you,
Yours faithfully,
Karishma Roy
Explanation:
Given :
Swati walks in a circle of radius 20m and minal walks in a circle of radius 40m.
Both complete one circle in same time.
To Find :
Relation between their speeds.
Solution :
❒ Speed is defined as the ratio of distance travelled to the time taken.
It is a scalar quantity having only magnitude.
SI unit : m/s
Distance covered by body after completing one round of circle will be equal to the perimeter of circle.
Let time taken by them to complete one round of circle be t..
A. Speed of swati :
➛ v = 2πr / t
➛ v = 2π(20) / t
➛ v = 40π / t .......... (I)
B. Speed of minal :
➛ v' = 2πr' / t
➛ v' = 2π(40) / t
➛ v' = 80π / t .......... (II)
From equation (I) and (II),
➠ v / v' = (40π/t) / (80π/t)
➠ v / v' = 1 / 2
➠ v' = 2v
∴ (c) Speed of minal is twice the speed of swati.Given :
Efficiency of the carnot engine changes from 1/6 to 1/3 when source temperature is raised by 100K.
To Find :
Temperature of sink.
Solution :
❒ Efficiency of carnot's engine (an ideal heat engine), is given by
η = 1 - T'/T
where,
T' denotes temp. of the sink
T denotes temp. of the source
Case - I :
➛ 1/6 = 1 - T'/T
➛ T'/T = 1 - 1/6
➛ T'/T = 5/6
➛ T = 6T'/5 .......... (I)
Case - II :
In this case temperature of the sink is raised by 100K..
➛ 1/3 = 1 - T'/(T + 100)
➛ T'/(T + 100) = 2/3
➛ 3T' = 2T + 200
From the equation (I),
➛ 3T' = 12T'/5 + 200
➛ 15T' - 12T' = 1000
➛ T' = 1000/3
➛ T' = 333.33k