Science, asked by Smallguddu, 7 months ago

You are measuring the current in a circuit that is operated on an 18v battery. The ammeter reads 40mA. Later you notice the current has dropped to 20mA. How much has the voltage changed

Answers

Answered by rehanaali6750

0

Answer:

please mark as brainiest you can find in Google

Answered by swan030782

6

Answer:

9V

Explanation:

40mA - 18V

then 20mA - (?)

20*18/40 = 9V

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