you Are on a ocean liner which run at 12 meter per second eastward you are running southward at 3.6 meter per second find the direction and magnitude of resultant velocity
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Explanation:
Given you Are on a ocean linear which run at 12 meter per second eastward you are running southward at 3.6 meter per second find the direction and magnitude of resultant velocity
- We need to find the direction and magnitude of the resultant velocity.
- So we have
- The resultant velocity can calculated by using Pythagoras theorem.
- So AC^2 = AB^2 + BC^2
- = 12^2 + 3.6^2
- = 144 + 12.96
- = 156.96
- So AC = √156.96
- = 12.52 m/s
- Now tan theta = 3.6 / 12
- = 0.3
- So theta = tan^-1 0.3
- = 16.699 degree
- So 16.699 degree to the east direction
Reference link will be
https://brainly.in/question/8706837
Answered by
3
Answer:
east direction 16.699 will be the answer
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