You are provided with hundred 1 ohm resistors. How can you combine these resistors to obtain
i) Highest
ii) Lowest possible values of resistance?
Which device can help to maintain potential difference across a conductor?
Answers
Answer:
We are given 100 resistors each of 1 ohm.
We need to connect them to get either highest resistance or lowest resistance.
We know, in series connection we get highest resistance possible and in parallel connection we get the lowest resistance possible.
Hence,
i) To get the highest possible value of resistance with hundred 1 ohm resistors, they should be connected in series.
ii) To get the lowest possible value of resistance with hundred 1 ohm resistors, they should be connected in parallel.
➸ The device which help in maintaining potential difference across a conductor is Battery or cell.
FORMULA TO FIND RESISTANCE IN DIFFERENT CONNECTIONS :
- Series - Rs = R1 + R2 +....+ Rn
- Parallel - 1/Rp = 1/R1 + 1/R2 +...+ 1/Rn
ANSWER
(I)Series
(ii)paralalel
EXPLANATION
mathematical proof
when resistance connected in series
equivalent resistance
Req = r1+r2+.......r100
Req = 100 ohm
when these are connected in parallel
1/Req = 1/r1+1/r2+.....1/r100
1/Req= 100
Req= 1/100 ohm
mathmaticl proof for any value of resistor
when these are connected in series
Rs = r1+r1.... r1 ( 100 times)
Rs = 100 r1 ................ 1
when these are connected in parallel
1/Rp = 1/r1+1/r2
Rp = r1r1/r1+r1 (100 times)
Rp = r1/100 ......... 2
divide 1 by 2
Rs/Rp =
Rs = 10000 Rp
means Rp is 10000 smaller then Rs.
battery is the instrument wh8ch maintain potential difference .
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