you are provided with mixture of nepthalene and clay .Suggest an activity to separate them with well labelled diagram.
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The mixture of naphthalene and sodium chloride can be separated by the process of sublimation as naphthalene is a sublime, i.e. it turns into vapour without changing in liquid and its vapour change into solid without changing into liquid, while sodium chloride is not a sublime.
Activity:
Materials required – China glass, funnel, tripod, gas burner, spatula, cotton.
Process:
• Take the mixture in a china glass.
• Put it on the tripod.
• Cover the mixture with a funnel by putting it inverted on the china glass.
• Plug the tip of the funnel using some cotton.
• Now start heating the china glass containing mixture.
• Stop heating after 30 to 60 second when vapour starts rising in the funnel.
• Leave the apparatus to get cooled.
• You will observe that naphthalene gets deposited on the inner wall of the funnel because of sublimation leaving the sodium chloride in the china glass.
• Scratch out the naphthalene deposited on the inner wall of the funnel.
Using this process the mixture of naphthalene and sodium chloride can be separated. Hope this helps you
Activity:
Materials required – China glass, funnel, tripod, gas burner, spatula, cotton.
Process:
• Take the mixture in a china glass.
• Put it on the tripod.
• Cover the mixture with a funnel by putting it inverted on the china glass.
• Plug the tip of the funnel using some cotton.
• Now start heating the china glass containing mixture.
• Stop heating after 30 to 60 second when vapour starts rising in the funnel.
• Leave the apparatus to get cooled.
• You will observe that naphthalene gets deposited on the inner wall of the funnel because of sublimation leaving the sodium chloride in the china glass.
• Scratch out the naphthalene deposited on the inner wall of the funnel.
Using this process the mixture of naphthalene and sodium chloride can be separated. Hope this helps you
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