you are provided with the following labelled samples which has highest weight 1 gram Ammonia 1 litre Ammonia one gram mole ammonia
Answers
Answer:
Explanation:Answer:
Here's what I got.
Explanation:
Let's start by picking a sample of this ammonia solution that has a volume of
1.0 L
=
1.0
⋅
10
3
mL
Use the density of the solution to convert its volume to mass.
1.0
⋅
10
3
mL solution
⋅
0.90 g
1
mL solution
=
900. g
Now, you know that the solution is
15
%
ammonia, presumably by mass. This tells you that every
100 g
of this solution contain
15 g
of ammonia.
In this case, your sample will contain
900
.
g solution
⋅
15 g NH
3
100
g solution
=
135 g NH
3
Next, use the molar mass of ammonia to convert the mass to moles.
135
g
⋅
1 mole NH
3
17
g
=
7.94 moles NH
3
As you know, the molarity of a solution tells you the number of moles of solute present in exactly
1 L
of the solution. Since our initial sample had a volume of
1.0 L
, you can say that you get
7.94
moles of ammonia, the solute, for every
1.0 L
of the solution.
This means that the molarity of the solution is
molarity = 7.9 mol L
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