You are provided with three similar but slightly different tuning fork when a and b are both struck, a beat frequency of fab is heard...
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either | fAB + fBC | or | fAB – fBC | will be heard
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' You are provided with three similar, but slightly different, tuning forks, when A and B are both struck, a beat frequency of f AB is heard. When A and C are both struck, beat frequency of f AC is heard. It was noticed that f AB<f AC . This experiment is repeated after coating tuning fork A with a little wax. Now it is observed that values of both f AB and f AC increase. Which tuning fork has the highest frequency? '
Answer:
f (A) > f (B) > f (C).
Explanation:
- Beats are formed when the two superposing wave trains are of nearly equal frequencies travelling with the same speed and in the same direction.
- Number of Beats per second, i.e., beat frequency is equal to difference between the two frequencies.
Given that :
- Beat frequency of A and B is f (AB)
- Beat frequency of A and C is f (AC)
- f (AB) < f (AC)
- After waxing fork A , f (AB) and f (AC) increases.
Solution :
- Since, f (AC) > f (AB) . f (C) is greater than f (B).
- After waxing A both beat frequency increases.
- Hence, f (A) > f (B) > f (C)
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