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A container of depth H is filled with two immiscible transparent liquids of refractive index Hi and p2 respectively. The depth of each
liquid is H/2. When viewed from above the apparent depth of the vessel is:-
Н H
24 242
OH
H
24 242
13
Hus
H
+
24 242
17
21
OH
Hus
24 242
25​

Answer 1

Answer:

Apparent depth of first liquid =

2μ

1

H

Apparent depth of second liquid =

2(μ

1

/μ

1

)

H

∴ Total apparent depth =

2μ

1

H

+

2μ

2

Hμ

1

=

2

H

[

μ

1

1

+

μ

2

μ

1

]

Explanation:

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Answer 2

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