Question

You are required to make a water bath of 50 kg at 45°C,by mixing hot water at 90°C , with cold water at 20°C. Calculate the amount of hot water required.
(SHC of water = 4.2 J/g°C)
plz answer ASAP

Answer 1

Hint: Let amt. of hot water x
Amount of cold water = (50
x) kg
Answer:
Total mixture of water- 50 kg
Resulting temp. e°C
Let mass of hot water-x kg
mass of cold water (50-x) kg
Heat lost by hot water- Heat gained by cold water
mc (T-θ) = mC (9-1)
x4200 (90-45)-(50-x) 4200 (45-20)
45x 25 (50-x)
45x = 1250-25x
45x + 25x = 1250
70x= 1250
1750
70
Mass of hot water
= 17.871 k