You are riding your bicycle directly away from a stationary source of sound and hear a frequency that is 1.4% lower than the emitted frequency. If the speed of sound is 344 m/s, what is your speed?
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I'll assume classical physics, and not relativistic physics. This means we have the formula:
F(bike)/F(source) = (v(sound) + v(bike))/v(sound) = 0.99
That is relatively easy to solve:
v(bike) = 0.99 * v(sound) - v(sound)
We could have instantly gone to that relation by stating
v(bike) = 0.01 * v(sound)
The bike is going 3.43 m/s
F(bike)/F(source) = (v(sound) + v(bike))/v(sound) = 0.99
That is relatively easy to solve:
v(bike) = 0.99 * v(sound) - v(sound)
We could have instantly gone to that relation by stating
v(bike) = 0.01 * v(sound)
The bike is going 3.43 m/s
Answered by
3
I'll assume classical physics, and not relativistic physics. This means we have the formula: F(bike)yF(source)- (V(sound) + v(bike)/ v(sound) 0.99 That is relatively easy to solve: v(bike) 0.99 * v(sound) v(sound) We could have instantly gone to that relation by stating v(bike) 0.01 * v(sound) The bike is going 3.43 m/s
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