You are riding your bicycle directly away from a stationary source of sound and hear a frequency that is 1.4% lower than the emitted frequency. If speed of sound is 344m/s, what is your speed?
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I'll assume classical physics, and not relativistic physics.
This means we have the formula:
F(bike)yF(source)- (V(sound) + v(bike)/ v(sound) 0.99
That is relatively easy to solve:
v(bike) 0.99 * v(sound) v(sound)
We could have instantly gone to that relation by stating v(bike) 0.01 * v(sound)
The bike is going 3.43 m/s
This means we have the formula:
F(bike)yF(source)- (V(sound) + v(bike)/ v(sound) 0.99
That is relatively easy to solve:
v(bike) 0.99 * v(sound) v(sound)
We could have instantly gone to that relation by stating v(bike) 0.01 * v(sound)
The bike is going 3.43 m/s
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