Question

You are selecting a cricket team of first 11 player's out of 16 including 4 bowlers and 2 wicket keeper. In how many ways you can do it so that the team contains exactly 3 bowlers and 1 wicket- keeper?
Hint: Permutation and Combination
Pls no spamming​

Answer 1

Answer: hey friend this is your answer

My solution:

Choosing 3 bowlers out of 4: (43)

Choosing 1 wicket keeper out of 2: (21)

Choosing the remaining 4 players out of 12: (127)

Hence, total permutations=(43)(21)(127)=6336

hope it help u mark me

Answer 2

For selecting 3 bowlers out of 4 bowlers = 4C3 = 4

For selecting 1 wicketkeeper from 2 = 2C1 = 2

Remaining Players = 16 - (1 + 3 )

= 12

We have to select 7 players from 12 remaining players = 12C7 = 693

Total no. of ways = 693 × 4 × 2

= 5544 ways