You are standing on a road. 100 m in front of you, there is a bus at rest. The bus is facing North and you are facing North as well. You start running at a speed of 20 m/s and at the same time the bus starts moving with a constant acceleration of 2 m/s². At what time will you be able to catch the train?
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You haven't mentioned any train earlier
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here we know that both get 200m dist in 10 sec.. therefore man will catch the bus in 10 s.
note :- we will take only even time like 2s,4s etc.
& we have started taking time 6s bcz it is the first no. which will be multiply by 20 to give more than 100m
qstn is solver by unitary method i.e. taking value one by one.
note :- we will take only even time like 2s,4s etc.
& we have started taking time 6s bcz it is the first no. which will be multiply by 20 to give more than 100m
qstn is solver by unitary method i.e. taking value one by one.
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