Physics, asked by PhysicsHelper, 1 year ago

You are standing with your bag in your hands on the ice in the middle of a pond. The ice is so slippery that it can offer no friction. How can you come out of the ice?

Answers

Answered by tiwaavi
18

There are the number of ways by which we can throw the bag from the Ice to outside. The most common way is of the Newton's third law of the motion.

According to me, If I will be on the middle of the Pond then I would throw my bag horizontally in opposite direction. Due to this, the Bag will exert the Equal and Opposite force on me.

Now, Ice is slippery, this means the coefficient of Friction is zero there, thus due to the force from the bag I will move away and will reach the corner of the ice. After this, I can come out easily from there.

Since, Physics is incomplete without the Mathematics, Let us derive the magnitude of the Force acting on me.

Let the mass of the bag be m and my mass be M. When I thrown the bag with the velocity v, then the bag pushed me with velocity V.

∴ MV = mv.

This is the force acting on me.


Hope it helps.

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