You are supplied with three resistors having 2 ohm 3 ohm and 6 ohm in what way it can be connected to get the resistance 4 ohm and 1 ohm
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Connect the Resistors 3 Ohm and 6 Ohm in parallel and the resulting resisistance is 1/(1/3+1/6) = 18/(6+3) = 2 Ohm . Let A and beB be the terminals to which they are connected. Let the resistor 2 Ohm be connected in series to this 3Ohm and 6 Ohm parallel group resistors. Now the total resistance of the circuit is 2Ohm+2Ohm= 4 Ohm.
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