Question

You are using a 2252Ω thermistor, β = 3940, and you measure a resistance of 672.5 ohms. What is the temperature in °C that you are measuring?
(Type in a one-decimal nu,ber)

Answer 1

Answer:35.5°C

Explanation:

You are using a 2252Ω thermistor, β = 3940, and you measure a resistance of 672.5 ohms. What is the temperature in °C that you are measuring?

Answer 2

Answer:55 degree Celsius

Explanation:The formula used is

T=[ 1/T' + ( ln Rt/R' )/B ] ^-1

Where T is the temperature in k

T' is the temperature at 0 degree Celsius i.e 298.2 k

ln is the natural log

Rt is the resistance that we have measured i.e 672.5 ohms

R' is the resistance of the thermistor i.e 2252 ohms

B is beta i.e 3940

By solving all these , we will get the answer in Kelvin (328.22 k )

But we want the answer in degree Celsius

So we will subtract 298.2 from 328.22

And also we need the answer in one decimal number so it will be 55