YOU CAN ALSO REPEAT THE NUMBERS....
Answers
Answer:
Firstly I will show you it is not possible by direct sum, then I’ll demonstrate the different ways to do so.
Not Possible by direct sum in base 10, because
If you take the numbers to be modulo 2, five odd numbers would sum up to 1, but 30 is 0 modulo 2
Step-by-step explanation:
why :-
Prerequisites:- Knowledge of basic Mathematics.
Prerequisites:- Knowledge of basic Mathematics.Number’s are odd numbers
Prerequisites:- Knowledge of basic Mathematics.Number’s are odd numbers1=2*0+1
3=2*1+1
5=2*2+1
5=2*2+1.
5=2*2+1.13= 2*6+1
15= 2*7+1
Or we can say that 2*n+1 is an odd number
Or we can say that 2*n+1 is an odd numberNow
Or we can say that 2*n+1 is an odd numberNowwe can say that the number we have to prove.
To prove : x+y+z=30
x+y+z=30For all x,y,z ∈ 2n+1 where n∈N(Natural numbers).
x+y+z=30For all x,y,z ∈ 2n+1 where n∈N(Natural numbers).Proof:-here’s no combination. It’s impossible. Every number in that list is odd.
x+y+z=30For all x,y,z ∈ 2n+1 where n∈N(Natural numbers).Proof:-here’s no combination. It’s impossible. Every number in that list is odd.We know that any even number can be expressed as 2n where n is an integer. Any odd number can be expressed as 2n−1.
x+y+z=30For all x,y,z ∈ 2n+1 where n∈N(Natural numbers).Proof:-here’s no combination. It’s impossible. Every number in that list is odd.We know that any even number can be expressed as 2n where n is an integer. Any odd number can be expressed as 2n−1.Let m, n, and k all be integers. Then the sum of three odd numbers can be written as:
(2m−1)+(2n−1)+(2k−1)
=2(m+n+k−1)−1.
Note that m+n+k−1 is another integer. If we call it N then the result is simply
2N−1
2N−1which, as we know is an odd number. Therefore the sum of three odd numbers is always an odd number.
2N−1which, as we know is an odd number. Therefore the sum of three odd numbers is always an odd number.Hence Proved.
13,6,11
Step-by-step explanation:
13 + 6 + 11 = 30
In above 9 can be rotated to 6