Question

You can answer any one you know and if you know them both please answer both! Thank You!

1. In the given figure if AD is the bisector of ∠A, show that AC > CD. [FIGURE below].
2. In the given figure ΔCPD = ΔBPD and AD is the bisector of ΔBAC. Prove that ∠BAP = ∠CAP and hence BP = CP. [FIGURE below]

Answer 1

Answer:

there ain't any figure dawg