Question

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Difference between outermost and innermost zones of the flame?​

Answer 1

Answer:

Answer:

\sf\tt\large{\green {\underline {\underline{⚘\;Question:}}}}

⚘Question:

Mr.X is driving to school to computes the average speed for his trip to be 50km/hr and on his return trip along the same route the average speed is 60km/hr .What is the average speed of his entire trip.

\sf\tt\large{\red {\underline {\underline{⚘\;Answer:}}}}

⚘Answer:

V _{a}v = 54.54km \: per \: hourV

a

v=54.54kmperhour

\sf\tt\large{\blue {\underline {\underline{⚘\;Solution:}}}}

⚘Solution:

Here , we should use the formula that is ,

average \: distance = \frac{totl.distance}{time \: taken}averagedistance=

timetaken

totl.distance

From this we get the answer to the solution.

Here the entire formula according to the given question is given below.

Let, calculate by applying all the values,

V _{a}v = \frac{2v1v2}{v1 + v2}V

a

v=

v1+v2

2v1v2

vav = \frac{2 \times 50 \times 60}{50 + 60} = \frac{6000}{110} = 54.54km \: per \: hourvav=

50+60

2×50×60

=

110

6000

=54.54kmperhour

\sf\tt\large{\green {\underline {\underline{⚘\;The \;average\;speed \;of \; entire\;trip \;is \;54.54km/hr:}}}}

⚘Theaveragespeedofentiretripis54.54km/hr:

2》

\sf\tt\large{\green {\underline {\underline{⚘\;Given:}}}}

⚘Given:

Find the momentum of body of mass 500 gm when moving with 120 m /sec in SI unit.

\sf\tt\large{\green {\underline {\underline{⚘\;Solution:}}}}

⚘Solution:

Here,

Mass of the given body 500g=0.5kg

P=m×v

Now applying all the values we get that,

P=0.5×120

P=60kg m/s.

\sf\tt\large{\red {\underline {\underline{⚘\; Momentum \;is \;60kg m/s:}}}}

⚘Momentumis60kgm/s:

Hope it helps u mate .

Thank you .