Question

you can do this in please try to answer my question ​

Answer 1

let BD = 3x

and CD =2x

as AD is perpendicular to BC

Therefore,

$\frac{area(abc)}{area(adc)} = \frac{ \frac{1}{2} \times ad \times bc }{ \frac{1}{2} \times ad \times cd} = \frac{3x + 2x}{2x} = \frac{5x}{2x} = \frac{5}{2}$
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