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from the given figure we came to know that it is a llgm
Let ODA be a triangle
OD = OA [ ∵diagonals bisect each other in a llgm ]
∴∠ODA = ∠OAD
60° = 60°
By ASP of a triangle
a+b+c = 180°
60°+60°+c=180°
c=180°-[60°+60°]
c=60°
∴∠AOD = 60°
∠OBC = ∠ODC [ ∵ alternate angles ]
∴ ∠OBC = ∠ODC = 60°
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