Question

You can solve the problem ​

Answer 1

Answer:

from the given figure we came to know that it is a llgm

Let ODA be a triangle

OD = OA [ ∵diagonals bisect each other in a llgm ]

∴∠ODA = ∠OAD

60° = 60°

By ASP of a triangle

a+b+c = 180°

60°+60°+c=180°

c=180°-[60°+60°]

c=60°

∴∠AOD = 60°

∠OBC = ∠ODC [ ∵ alternate angles ]

∴ ∠OBC = ∠ODC = 60°