Question

you can't give complete solution of it​

Answer 1

Answer:

(B) -1,1

Step-by-step explanation:

Given , the equation :

x² + px + (1- p) = 0

Here ,

a = 1

b= p

c = (1 - p )

And one root of the equation is

(1- p).

Let the other root be ß

Now ,

$sum \: of \: the \: roots \: = \frac{ - b}{a} \\ \\ \implies(1 - p) + \beta = \frac{ - p}{1} \\ \\ \implies1 - p + \beta = - p \\ \\ \implies \beta = - p + p - 1 \\ \\ \implies \beta = - 1$

Again ,

$product \: of \: the \: roots \: = \frac{c}{a} \\ \\ \implies(1 - p)\beta = (1 - p) \\ \\ \implies \beta = \frac{1 - p}{1 - p } \\ \\ \implies \beta = 1$

Therefore , the other root is -1 or 1