you changes placed in vacuum experience force of 4*10-³ n if a dielectric medium of k=2 dielectric constant is placed in between them.calculate the new force
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F= kq1q2/r²
F=2×q1q2/4π€€r
Force is inversely proportional to dielectric constant of the medium
F1=F/2=2×10^-3
I hope this helps
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