You draw a card and get an ace and without replacing this card you draw another card and this time you get king. what is the probability of first getting an ace and then getting a king
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No. of ace =4
No. of kings =4
Total no. of cards (ace and kings)=4+4=8
Probability =8 /52
=1/9
No. of kings =4
Total no. of cards (ace and kings)=4+4=8
Probability =8 /52
=1/9
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The probability that the first card drawn is an Ace is 4by52. Given that an ace was drawn first, there are 51 cards left, so the (conditional) probability that a King is drawn next is 4by51. Thus our required probability is 4by52⋅4by51
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