You drop a 5 kg ball from a height of 2 m. Just before it reaches the ground, how much kinetic energy does it have?
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At the height of 2 m, K.E is 0 J and potential as mgh=5*2*10=100 J.
Hence at lowest height, the Potential energy should be converted into the kinetic. Hence, the KE of the ball should be 100 J just before touching the ground.
ANSWER=>100J
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Answer:
The given ball possess a Kinetic Energy of 100J just before reaching the ground.
Explanation:
Given is a ball of mass 5kg which is released from a height of 2m.
Potential Energy of the ball just before reaching ground=0
Potential Energy of the ball at a height of 2m =mgh =5×10×2=100J
After the ball reaches ground its complete potential energy changes to kinetic energy,
So, kinetic energy of the ball just before reaching ground=100J.
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