Question

You guys plzz help me to solve (a) part plzz guys help me to solve my question plzzzz....

Answer 1

hey
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•when bases are same and its in multiplication

•then a formula is used

a/b^m * a/b ^m = a/b^ (m+n)

(a) solution

3/5^(-2+9+-8)
3/5 ^(-10+9)
3/5^(-1)
5/3

•when bases are same formula to be used are and its in divison

•a/b^m÷a/b^n = a/b(m-n)

(b) 3/5^(-7+5)
3/5^(-2)
5/3^(2)
25/9

hope helped
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Answer 2

$\huge{\bold{\underline{\underline{Heya!!}}}}$

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Your Answer Goes Here.........

Some Formulae to be remembered for this Are :-

•
$\frac{ {a}^{n} }{ {a}^{m} } = {a}^{n - m}$
.....1)

•
${a}^{n} \times {a}^{m} = {a}^{n + m}$
.........2)

a)
${( \frac{3}{5}) }^{ - 2} \times ( { \frac{3}{5}) }^{8} \times { (\frac{3}{5}) }^{9} \\ \\ = ( { \frac{3}{5}) }^{ - 2 + 8 + 9} \\ \\ = ( { \frac{3}{5}) }^{15}$
From. 2)

b)(3/5)^-7/(3/5)^-5

=>(3/5)^-7-(-5)

=>(3/5)^-7+5

=>(3/5)^-2. From 1)

$\huge{\bold{\underline{\underline{Thanks}}}}$✌️