Question

You have 12 Mohms of resistance, 9 amps of current, what is the voltage within the circuit?​

Answer 1

 $\bf{ \underline{Given:- }}$

$\sf• \: We \: have \: 12 \: ohms \: of \: resistance, \: 9 \: amps \: of \: current.$

$\bf{ \underline{To \:  Find :- }}$

$\sf{• \:  The  \: Voltage\: within \: the\: circuit.  }$

$\huge\bf{ \underline{ Solution:- }}$

$\sf According  \: to  \: the  \: question,$

$\sf•  \: Current \:  (I) = 9  \: Amps.$

$\sf• \:  Resistance  \: (R) = 12 \:  Ω$

 

$\sf{We \:  know \: that, }$

$\bf \red{ \bigstar{ \: V = IR }}$

$\rightarrow \sf V = 9 \times 12$

$\rightarrow \sf V = 108$

$\sf \purple{Therefore, \:  the \:  voltage \: within \: the \: circuit \: is  \: 108  \: v \: .}$

Answer 2

Answer:

Given: R = 12 ohms

I = 9 A

Using ohm's law

i.e. V = IR

V = 12 × 9

V = 108 volts.