Question

You have 27g of each reactant. Which is the limiting reactant in the production of aluminium oxide?

Answer 1

Answer:

2Al+

2

3

O

2

⟶Al

2

O

3

Moles of Al=

27

27

=1 mol

2 mole Al gives

2

3

mole O

2

1 mole Al gives

4

3

mole O

2

Mass of oxygen =

4

3

×32=24 gram

Hence, the correct option ios (A)