you have a lock 15 cubic centimetres mass of 45kg.what is the density? plzz answer fast . it's an emergency.
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Density, ρ = mass/volume.
Given :- Volume, V = 15 cm3 = 1.5 ×10-5 m3 (Convert volume from CGS unit to SI unit)
Mass, m = 45 kg
D e n s i t y space o f space l o c k comma
space rho space equals m over V space equals space fraction numerator 45 over denominator open parentheses 1.5 cross times 10 to the power of negative 5 end exponent close parentheses end fraction equals space 30 cross times 10 to the power of 5 space k g divided by m cubed space equals space 3 space cross times space 10 to the power of 6 space k g divided by m cubed space
Thus, density of the lock is 3×106 kg/m3
Given :- Volume, V = 15 cm3 = 1.5 ×10-5 m3 (Convert volume from CGS unit to SI unit)
Mass, m = 45 kg
D e n s i t y space o f space l o c k comma
space rho space equals m over V space equals space fraction numerator 45 over denominator open parentheses 1.5 cross times 10 to the power of negative 5 end exponent close parentheses end fraction equals space 30 cross times 10 to the power of 5 space k g divided by m cubed space equals space 3 space cross times space 10 to the power of 6 space k g divided by m cubed space
Thus, density of the lock is 3×106 kg/m3
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