Question

You have a sample of neon gas at a certain pressure, volume, and temperature. You double the volume, double the number of moles of neon, and double the Kelvin temperature. How does the final pressure (Pf) compare to the original pressure (Po) ?

Answer 1

Assuming the gas to be Ideal,

So Earlier:

(Po) V= nRT. - - - - - - - -> (1).

Later,

(Pf) *2V= 2n*R*2T

(Pf) *V= 2nRT. - - - - - - -> (2).

Dividing (1) by (2) :

Po/Pf= 1/2

2Po=Pf

or Po= Pf/2