you have a sister whose age is twice the age of your younger brother. your brother is 1/11 the age of your father who is 2 years older than your mother. Your age is 1/8 of your mother. what is your age
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Answer:
Step-by-step explanation:
LET , THE AGE OF SISTHER = Y YEARS OLD
AND , THE AGE OF BROTHER = X YEARS OLD
AND , THE AGE OF FATHER = Z YEARS OLD
AND , THE AGE OF MOTHER = A YEARS OLD
AND , THE AGE OF ME = B YEARS OLD
NOW ,
ACCORDING TO QUESTION
2Y = X
AGAIN ,
2Y/11 = Z
AGAIN ,
2Y - 22 / 11 = A
AGAIN ,
2Y -22 / 88 = B
Y - 11 / 44 = B
HENCE , THE AGE OF ME = Y -11 / 44
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