You have a spring with a spring constant of 150 n/m. how much will it lengthen by if you apply a force of 3 n?
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2
Answer:
.02 m , apply F= k×∆x.. where ∆x represents change in length
Answered by
1
Answer:
F=kx
3= 150×X
x = 3/150 m= 300/150cm =2cm
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