Chemistry, asked by oulajuneid, 2 months ago

You have been asked to calculate the enthalpy change in the following reaction: 2Al(s) + Fe2O3(s) → Al2O3(s) + 2Fe(s) The reaction occurs in the following stages:

1. 2Al(s) + Fe2O3(s) → Al2O3(s) + 2Fe(l) ΔH = -732.5kJ mol–1

2. Al2O3(s) + 2Fe(l) → Al2O3(s) + 2Fe(s) ΔH = -27.6kJ mol–1

3. Al2O3(s) + 2Fe(l) → Al2O3(s) + 2Fe(s) ΔH = -91kJ mol–1

Note stages 2 and 3 look the same, but the reaction is cooling from 1700oC to 25oC and hence the enthalpy change there. Calculate the overall enthalpy change for the reaction. You must show your workings within your submission, and explain your reasoning. Your explanation should be a maximum of 200 words.

Answers

Answered by sakshi1158
0

Answer:

You have been asked to calculate the enthalpy change in the following reaction: 2Al(s) + Fe2O3(s) → Al2O3(s) + 2Fe(s) The reaction occurs in the following stages:

1. 2Al(s) + Fe2O3(s) → Al2O3(s) + 2Fe(l) ΔH = -732.5kJ mol–1

2. Al2O3(s) + 2Fe(l) → Al2O3(s) + 2Fe(s) ΔH = -27.6kJ mol–1

3. Al2O3(s) + 2Fe(l) → Al2O3(s) + 2Fe(s) ΔH = -91kJ mol–1

Note stages 2 and 3 look the same, but the reaction is cooling from 1700oC to 25oC and hence the enthalpy change there. Calculate the overall enthalpy change for the reaction. You must show your workings within your submission, and explain your reasoning. Your explanation should be a maximum of 200 words.

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