Question

You have been given an array of size N consisting of integers. In addition you have been given an element M you need to find and print the index of the last occurrence of this element M in the array if it exists in it, otherwise print -1. Consider this array to be 1 indexed.

Answer 1

Please refer the attached image

Answer 2

Answer:

The following Python program solves the stated problem:

arr = list(map(int,input().split()))

n = int(input())

m = int(input())

for i in range(n-1,-1,-1):

 if(arr[i]==m):

    return i+1

return -1

Explanation:

Let's understand the code:

• First, we take the array input and size of the array N by the user.
• m represents that element that is to search in the given array.
• Since we want to print the index of the last occurence occurrence of the m element. So we have to start the for loop from the backward of the array.
• Each time element of the array is compared with the m element. If they match then we return i+1. Since the problem is mentioning the array to be 1 indexed.
• But if the m element is not found then we return -1.

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