Question

- You have given 4.25 g NH3(g).
Given : at. wt. of N-14; H-1
Which of the following is/are correct regarding above NH3?
(a) It contains 0.25 mole of NH3.
(c) It contains total of 1.0 mole of N and H atoms.
(b) It contains 0.75 mole of H-atom.
(d) It contains approximately 1.5 x 1023 molecule​

Answer 1

Answer:

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Explanation:

your correct option(s) are --

(a) it contains 0.25 mole of NH3.

Answer 2

To find out the correct option, one can easily calculate the number of atoms and moles $NH_{3}$.

Moles in 4.25g $NH_{3}$:

• The Number of moles = given mass/molar mass
• The number of moles = 4.25/(14+1+1+1)
• The number of moles = 4.25/17
• The number of moles = 0.25

Moles of N and H atom.

• 1 molecule $NH_{3}$ contains 1 atom of N and 3 atoms of H.
• 1 mole $NH_{3}$ contains NA atoms of N and 3NA atoms of H.
• 0.25 mole $NH_{3}$ contains 0.25NA atoms of N and 0.75NA atoms of H.
• Total number of atoms present = 0.25NA + 0.75NA = NA
• So there are 1 mole N and H atoms present.

The number of molecules in 4.25g $NH_{3}$:

• Number of moles = molecules/NA
• 0.25 = molecules/NA
• molecules = $0.25 * 6*10^{23}$ = $1.5*10^{23}$

All the statements are correct.

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