You have three resistors of 9 ohms each. By combining them what can be (a) the highest resistance, and (b) the lowest resistance? (c) How can you combine them to get a resistanbe of 12 ohms?
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(a) three resistor will be connected in series (.b) two resistor will be connected in parallel and one resistor series
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the highest resistance will be obtained when they are connected in series I.e
R = 9 + 9 + 9
= 27 ohm
the lowest value of resistance Will be obtained when they are connected in parallel
I.e 1/R != 1/9 +1/9 + 1/9
R=3 ohm
(3) it is not possible to obtain 12 ohm from three restrictions of 9 ohm each.
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