You have three resistors of 9 ohms each. By combining them what can be (a) the highest resistance, and (b) the lowest resistance? (c) How can you combine them to get a resistanbe of 12 ohms?
Answers
Answered by
4
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~* THE ANSWER OF YOUR QUESTION IS..*~
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the highest resistance will be obtained when they are connected in series I.e
R = 9 + 9 + 9
= 27 ohm
the lowest value of resistance Will be obtained when they are connected in parallel
I.e 1/R != 1/9 +1/9 + 1/9
R=3 ohm
(3) it is not possible to obtain 12 ohm from three restrictions of 9 ohm each.
HOPE IT WILL HELP YOU
~* THE ANSWER OF YOUR QUESTION IS..*~
✍✍✍✍✍✍✍✍________________________________________
the highest resistance will be obtained when they are connected in series I.e
R = 9 + 9 + 9
= 27 ohm
the lowest value of resistance Will be obtained when they are connected in parallel
I.e 1/R != 1/9 +1/9 + 1/9
R=3 ohm
(3) it is not possible to obtain 12 ohm from three restrictions of 9 ohm each.
HOPE IT WILL HELP YOU
Answered by
6
hey mate ♡♡
here is your answer:-
《1》the highest resistance is obtained
when we combine. them in series
☆ 9+9+9= 27
《2》 the lowest resistance is obtained when we combine them in parallel
☆ 1/R = 1/9 +1/9 + 1/9
= 3/9
= 1/3
hence the resistance is 3
《3 》 it is not possible to combine them to obtained 12 ohm resistance
hope its helpful for you dear♡♡☆
here is your answer:-
《1》the highest resistance is obtained
when we combine. them in series
☆ 9+9+9= 27
《2》 the lowest resistance is obtained when we combine them in parallel
☆ 1/R = 1/9 +1/9 + 1/9
= 3/9
= 1/3
hence the resistance is 3
《3 》 it is not possible to combine them to obtained 12 ohm resistance
hope its helpful for you dear♡♡☆
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