Question

You have to Calculate the volume occupied by 11.2 g of the gas at NTP.

Given that the vapour density of a gas is 11.2.?​

Answer 1

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Molecular mass=2*vapour density

Molecular mass=2*vapour density =2*11.2

Molecular mass=2*vapour density =2*11.2=22.4 g

Molecular mass=2*vapour density =2*11.2=22.4 gAt NTP,

Molecular mass=2*vapour density =2*11.2=22.4 gAt NTP,volume occupied by 22.4 g of gas= 22.4 l

Molecular mass=2*vapour density =2*11.2=22.4 gAt NTP,volume occupied by 22.4 g of gas= 22.4 lvolume of 11.2g gas = 22.4/22.4*11.2

Molecular mass=2*vapour density =2*11.2=22.4 gAt NTP,volume occupied by 22.4 g of gas= 22.4 lvolume of 11.2g gas = 22.4/22.4*11.2= 11.2 l

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Answer 2

$\huge\mathbb\red{Theopekaaleader}$Molecular mass=2*vapour density

Molecular mass=2*vapour density =2*11.2

Molecular mass=2*vapour density =2*11.2=22.4 g

Molecular mass=2*vapour density =2*11.2=22.4 gAt NTP,

Molecular mass=2*vapour density =2*11.2=22.4 gAt NTP,volume occupied by 22.4 g of gas= 22.4 l

Molecular mass=2*vapour density =2*11.2=22.4 gAt NTP,volume occupied by 22.4 g of gas= 22.4 lvolume of 11.2g gas = 22.4/22.4*11.2

Molecular mass=2*vapour density =2*11.2=22.4 gAt NTP,volume occupied by 22.4 g of gas= 22.4 lvolume of 11.2g gas = 22.4/22.4*11.2= 11.2 l