you have tossed 2 coins find the probability of gettin 7 by sum
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Answer:
P(E)= 6/36.
Step-by-step explanation:
Sample = {(1,1) (1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)}
E = (Probability of getting sum 7)
E = {(1,6)(2,5)(3,4)(4,3)(5,2)(6,1)}
P(E) = 6/36
Not two coins ,two dice.
Hope it helps you.
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