you have two lenses A and B of focal length + 10 cm and minus 10 cm respectively state the nature and power of each lens which of the two lenses will form a virtual image and magnified image of an object placed at 8cm from the lens also draw the ray diagram
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given,
focal length of lens A is +10 cm.
focal length of lens B is -10 cm.
Finding power of lens A
P = 1/F (in m) then P = 100/F (in cm)
P = 100/+10 = +10 d, and this lens is convex lens.
Finding power of lens B
P = 1/F (in m) then P= 100/F (in cm)
P = 100/-10 = -10 d, and this lens is concave lens.
I hope this is helpful..............
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