Question

You have two metallic wires of resistance 6π and 3π . How will you connect this wires to get an effective resistance of 2π

Answer 1

Answer:

In parallel connection.

Explanation:

$\frac{1}{3\pi} + \frac{1}{6\pi} \\ = \frac{ 2 + 1}{6\pi} \\ = \frac{1}{2\pi} \\ \\ \\ \frac{1}{ r_{eff}} = \frac{1}{2\pi} \\ \\ { r_{eff}} = 2\pi$

Answer 2

Answer:you connect it in parallel connection.

Proof

1/6π + 1/3π

3/6π= 1/2 π

Therefore equivalent resistance= 2π..

Hence proved that parallel connection will result in equivalent resistance of 2π..

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Explanation: