Question

You have two metallic wires of resistances 6Ω and 3Ω. How will you connect these wires to get the effective resistance of less than 3Ω and 2Ω​

Answer 1

Explanation:

we can connect these wires in parallel way .therefore effective resistance becomes,

effective resistance=(6+3)/(6*3)

=9/18

=0.5 ohm

Answer 2

ANSWER:-

connect them in parallel connection

VERIFICATION:-

• R1=6Ω
• R2=3Ω

We know that

$\boxed{\sf \dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}}$

$\\ \sf\longmapsto \dfrac{1}{R}=\dfrac{1}{6}+\dfrac{1}{3}$

$\\ \sf\longmapsto \dfrac{1}{R}=\dfrac{1+2}{6}$

$\\ \sf\longmapsto \dfrac{1}{R}=\dfrac{3}{6}$

$\\ \sf\longmapsto \dfrac{1}{R}=\dfrac{1}{2}$

$\\ \sf\longmapsto {}{R}=2Ω$

Hence verified.