Question

You hired a taxi and travelled 10 km at 2:00 pm. If the minimum fare is Rs 14 and the fare goes on at the rate of Rs 7.20 per 200 meters, calculate the total fare that you paid.

Answer 1

200 m => 200/1000 km

=> 1/5 km

and fair of 1/5 km is 7.2 rupees

for 1 km 7.2×5 = 36 rupees

for 10 km 36×10 = 360 rupees

Answer 2

Answer:

Given,

Taxi fare for first kilometer = Rs. 10

Taxi fare for subsequent distance = Rs. 6

Total distance covered = x

Total fare = y

Since the fare for first kilometer = Rs. 10

According to problem,

Fare for (x - 1) kilometer = 6(x-1)

So, the total fare = 6(x-1) + 10

y = 6(x-1) + 10

y = 6x - 6 + 10

y = 6x + 4

Hence, y = 6x + 4 is the required linear equation.

x

-1

0

1

y

-2

4

10