Physics, asked by sajeeda77, 2 months ago

You plunge a basketball beneath the surface of a swimming pool until
half the volume of the basketball is submerged. If the basketball has a
radius of 12 centimeters, what is the buoyancy force on the ball due to
the water?
35 N​

Answers

Answered by HaritbaranM
0

Answer:

35 N or 35.49 newtons

Explanation:

To calculate the buoyancy force on the basketball, we can use the formula:

Buoyancy Force = Weight of the water displaced by the basketball

When the basketball is submerged halfway, it displaces a volume of water equal to half of its own volume. We can calculate the volume of the basketball using the formula for the volume of a sphere:

Volume of basketball = (4/3) x π x (radius)^3

= (4/3) x π x (12 cm)^3

= 7,238.23 cubic centimeters

Half the volume of the basketball is therefore 3,619.12 cubic centimeters.

We know that 1 cubic centimeter of water has a weight of 1 gram, or 0.001 kilogram. So the weight of the water displaced by the basketball is:

Weight of water displaced = Volume of water displaced x Density of water x Gravity

= 3,619.12 cubic centimeters x 0.001 kg/cubic centimeter x 9.81 m/s^2

= 35.49 N

Therefore, the buoyancy force on the basketball due to the water is approximately 35 N (newtons).

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