You project an image through a lens with a focal length of 19.7 cm If the object distance is 39.4 cm and it's height is 5.61 cm what is the height of the image
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An object of height 6 cm is placed perpendicular to the principal axis of a concave lens of focal length 5 cm. Use lens formula to determine the position, size and nature of the image if the distance of the object from the lens is 10 cm.
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Given : u=−10 cm f=−5 cm h
o
=6 cm
Using lens formula :
v
1
−
u
1
=
f
1
∴
v
1
−
(−10)
1
=
−5
1
⟹v=−
3
10
=−3.33 cm (- sign shows that image is virtual)
Also m=
h
o
h
i
=
u
v
∴
6
h
i
=
−10
3
−10
⟹h
i
=+2 cm (+ sign shows that image is erect)
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